X^2+2x=106

Solution for X^2+2x=106 equation:

X^2+2X=106

We move all terms to the left:

X^2+2X-(106)=0

a = 1; b = 2; c = -106;
Δ = b2-4ac
Δ = 22-4·1·(-106)
Δ = 428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{428}=\sqrt{4*107}=\sqrt{4}*\sqrt{107}=2\sqrt{107}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{107}}{2*1}=\frac{-2-2\sqrt{107}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{107}}{2*1}=\frac{-2+2\sqrt{107}}{2}
$